0=-2w^2+240w

Solution for 0=-2w^2+240w equation:

0=-2w^2+240w

We move all terms to the left:

0-(-2w^2+240w)=0

We add all the numbers together, and all the variables

-(-2w^2+240w)=0

We get rid of parentheses

2w^2-240w=0

a = 2; b = -240; c = 0;
Δ = b2-4ac
Δ = -2402-4·2·0
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-240)-240}{2*2}=\frac{0}{4}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-240)+240}{2*2}=\frac{480}{4}
=120
$